2.3t=10t^2

Solution for 2.3t=10t^2 equation:

2.3t=10t^2

We move all terms to the left:

2.3t-(10t^2)=0

determiningTheFunctionDomain
-10t^2+2.3t=0

a = -10; b = 2.3; c = 0;
Δ = b2-4ac
Δ = 2.32-4·(-10)·0
Δ = 5.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{5.29}}{2*-10}=\frac{-2.3-\sqrt{5.29}}{-20}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{5.29}}{2*-10}=\frac{-2.3+\sqrt{5.29}}{-20}
$